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6n^2+90n+336=0
a = 6; b = 90; c = +336;
Δ = b2-4ac
Δ = 902-4·6·336
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-6}{2*6}=\frac{-96}{12} =-8 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+6}{2*6}=\frac{-84}{12} =-7 $
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